J'ai postulé en ligne. J'ai passé un entretien chez IBS Software (Bangalore Rural) en juill. 2024
Entretien
I had interview at ibs software as java developer, there 3 rounds but i have attened two rounds ,second round was failed they have asked write java 8 program for find department has max employees and project,java,spring boot,mvc,java 8 related questions, its great experience for me, but i didn't selecetd for hr round, some how i have dissppointed, be confidence at interview, give anwsers clearly and more innovatily
Questions d'entretien [1]
Question 1
Java 8 related Questions,lamdas,Functional interface,spring boot annotations,mvc,sql queries
J'ai postulé via une agence de recrutement. J'ai passé un entretien chez IBS Software en août 2025
Entretien
The technical interview round included a combination of question-and-answer sessions, coding challenges, and basic SQL query problems. The Q&A section focused on assessing my understanding of core concepts relevant to the role, while the coding portion tested my problem-solving skills and logical thinking through hands-on programming tasks. Additionally, I was asked to write and interpret simple SQL queries to evaluate my grasp of database fundamentals
Questions d'entretien [1]
Question 1
Java Stream API and it uses and asked to write one example problem
J'ai postulé via un recruteur. J'ai passé un entretien chez IBS Software (Kochi) en juin 2025
Entretien
The interview process includes four rounds: a coding test, technical interview, manager discussion, and HR discussion. The entire selection process will be conducted in face-to-face mode at the designated location.
Questions d'entretien [1]
Question 1
You are required to design and implement a stack data structure that supports the following operations, all in O(1) time complexity:
1️⃣ push(x) — Pushes an integer x onto the stack.
2️⃣ pop() — Removes the element on the top of the stack.
3️⃣ top() — Gets the top element of the stack.
4️⃣ getMin() — Retrieves the minimum element currently in the stack.
5️⃣ getMax() — Retrieves the maximum element currently in the stack.