sorting based on hashmap value,string swapping, deadlock program.

Question

Utilisateur anonyme · Accepted Answer

HashMap map = new HashMap();
		map.put("Prakash", new Emp(10, "Prakash"));
		map.put("Trinadh", new Emp(5, "Trinadh"));
		map.put("Roksana", new Emp(1, "Roksana"));
		map.put("IsabellaWang", new Emp(2, "IsabellaWang"));
		List list = new ArrayList(map.values());
		Collections.sort(list);
		LinkedHashMap lmap = new LinkedHashMap();
		Iterator it = list.iterator();
		while (it.hasNext()) {
			Emp e = it.next();
			Iterator it1 = map.keySet().iterator();
			while (it1.hasNext()) {
				String e1 = it1.next();
				if (e.getName().equals(e1)) {
					lmap.put(e1, e);
				}
			}
		}
		System.out.println(lmap);
	}




2.public class Q1 {
String str1="java";
String str2="python";
Thread td1=new Thread("My Thread"){
	public void run(){
		while(true){
			synchronized(str1){
				synchronized(str2){
					System.out.println("the given one is:"+str1+str2);
				}
		}
		}
	}
};
Thread td2=new Thread("MY THREAD2"){
	public void run(){
		while(true){
			synchronized(str1){
				synchronized(str2){
					System.out.println("the other thread:"+str1+str2);
				}
			}
		}
	}
};
public static void main(String... a){
	Q1 q=new Q1();
	q.td1.start();
	q.td2.start();
}
}

3.String s1="Capgemini";
String s2="sabre";
//append 2nd string to first
s1=s1+s2;
//store initial string s1 in to a s2
s2=s1.substring(0,s1.length()-s2.length());
//store initial strings2 in strings1
s1=s1.substring(s2.length());
System.out.println("the first string is:"+s1+"................"+"and second one is:"+s2);

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