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Google
On a demandé à Local Data Quality Evaluator...10 juillet 2012

How many cows are in Canada

94 réponses

Let me Google it

Zero. There are no 'cows' in 'canada'. Or I guess 0.25 since they share the letter c. Moins

So by assuming cows are only used for milk production, the first two answers are already wrong. What about meat production? Moins

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Yahoo

Question was asked: "If you were on an island and could only bring 3 things, what would you bring?"

59 réponses

1. Iron Man Suit. 2. Not necessary. I have an Iron Man Suit. 3. Not necessary. I have an Iron Man Suit. Moins

Michael Phelps, a saddle, and a gold medal on a stick

1) A fully equipped and provisioned yacht, a nice 100 foot model, something I can land a helicopter on. 2) A helicopter to land on my yacht. 3) My lovely wife. Moins

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Apple

There are three boxes, one contains only apples, one contains only oranges, and one contains both apples and oranges. The boxes have been incorrectly labeled such that no label identifies the actual contents of the box it labels. Opening just one box, and without looking in the box, you take out one piece of fruit. By looking at the fruit, how can you immediately label all of the boxes correctly?

46 réponses

Swaz answer is almost correct however it does not work in all scenarios. lets assume: box 1 is labelled Oranges (O) box 2 is labelled Apples (A) box 3 is labelled Apples and Oranges (A+O) and that ALL THREE BOXES ARE LABELLED INCORRECTLY" Pick a fruit from box 1, 1) if you pick an Orange: - box 1's real label can only be O or A+O - box 1's current label is O - since ALL LABELS ARE INCORRECT then box 1's real label can not be O - box 1's new label should then be A+O by elimination - since ALL LABELS ARE INCORRECT - box 2's label is changed to O - box 3's label is changed to A - SOLVED 2) if you pick an Apple: - box 1's real label can only be A or A+O - box 1's current label is O - since ALL LABELS ARE INCORRECT then box 1's real label can not be O - this still leaves us with the choice between label A and label A+O - which would both be correct - FAILURE Solution: The trick is to actually pick a fruit from the A+O labeled box Pick a fruit from box 3: 1) if you pick an Orange: - box 3's real label can only be O or A - box 3's current label is A+O - since ALL LABELS ARE INCORRECT then box 3's real label can not be A+O - box 3's new label should then be O by elimination - since ALL LABELS ARE INCORRECT - box 1's label is changed to A - box 2's label is changed to A+O - SOLVED 2) if you pick an Apple: - box 3's real label can only be O or A - box 3's current label is A+O - since ALL LABELS ARE INCORRECT then box 3's real label can not be A+O - box 3's new label should then be A by elimination (not O) - since ALL LABELS ARE INCORRECT - box 1's label is changed to A+O - box 2's label is changed to O - SOLVED Moins

All the three boxes are names incorrectly. SO the bax lebeled Apples+Oranges contains only Oranges or Only Apples. Pick one fruit from it. If it is Orange then lebel the box as Orange. So the box lebeled Oranges contains Apples and the remaining contains both. Moins

It's easier to draw it out. There are only 2 possible combinations when all labels are tagged incorrectly. All you need to do is pick one fruit from the one marked "Apples + Oranges". If it's Apple, then change "Apple + Orange" to "Apple" The "Apple" one change to "Orange" The "Orange one change to "Apple + Orange" If it's Orange, then change "Apple + Orange" to "Orange" The "Apple" one change to "Apple + Orange" The "Orange" one change to ""Apple" Moins

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Google

Do you have any questions?

44 réponses

read the topics mentioned in the mail you have received from Google reg interview. Be ready for any google's product analysis. Present your views proactively. It will be so friendly interview that you wouldn't feel that you are actually going through it. They check thought processing speed and different thinking. Relax and give your best. Moins

I got a call from the HR within a couple of hours confirming that I'm through to the next round. I think the official mail came in about a day or two. Moins

oh ok i'm yet to get that call from HR though the interview went good.

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Eze Software

You are in a dark room with no light . You need matching socks for your interview and you have 19 grey socks ans 25 black socks. What are the chances you will get a matching pair?

27 réponses

SC calculated the correct probability of getting WRONG socks if allowed to ONLY take 2 single socks from a mix of 19 single grey and 25 single black socks. The correct calculation is 942/1892 is the actual chance of getting a pair of either colour (don't care if they match the suit - since I don't know what colour suit I'm wearing, as it's dark, just that they match each other). This is 49.7%. Since this is less than an even bet, it is probably time to look for a creative solution (after providing the correct answer of course). I'm disappointed none of you checked the maths before providing the standard '3 socks make a pair' response - which I prefer anyway - or the selection of brilliant lateral thinking responses. (My wife kindly pairs my socks as I' colour blind anyway - so they always match each other - but seldom match my clothing.) Tara has obviously not read the question - 3 grey or 3 black socks does provide a matching pair. If I want a matching pair which ALSO matches my suit - then I need to be allowed more socks - 21 if I want a black pair, 27 if I want a grey pair - or of course 27 in the worst case if I don't know what suit I'm wearing, and it happens to be grey. Moins

There are (25 choose 2) unique combinations of black + (19 choose 2) unique combinations of grey out of a total of ((25+19) choose 2) unique combinations. 25 choose 2 = 25! / (2! * (25 - 2)!) = 300 19 choose 2 = 19! / (2! * (19 - 2)!) = 171 44 choose 2 = 44! / (2! * (44 - 2)!) = 946 (300 + 171) / 946 = 0.4979 = 49.79% probability, same as concluded by Mickey's correction of SC. Sorry 2easy, time to brush up on your probabilities. Moins

0.047

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BitTorrent

A dwarf-killing giant lines up 10 dwarfs from shortest to tallest. Each dwarf can see all the shortest dwarfs in front of him, but cannot see the dwarfs behind himself. The giant randomly puts a white or black hat on each dwarf. No dwarf can see their own hat. The giant tells all the dwarfs that he will ask each dwarf, starting with the tallest, for the color of his hat. If the dwarf answers incorrectly, the giant will kill the dwarf. Each dwarf can hear the previous answers, but cannot hear when a dwarf is killed. What strategy should be used to kill the fewest dwarfs, and what is the minimum number of dwarfs that can be saved with this strategy?

21 réponses

Think broadband communication. Exploit the capabilities of the communications medium. A minimum of nine dwarves can be saved based on the information provided in the original post I viewed. The strategy is for each dwarf to employ the expected language to communicate the color of their own hat to the giant, while simultaneously employing a vocal pitch protocol to indicate the color of the hat of the dwarf in front of him, high pitch for white and low pitch for black. The original post, indicates the dwarves may collude prior to the distribution of hats, so there is opportunity to negotiate such a simple broadband communication protocol. The tallest dwarf only has a 50/50 chance since the number of black and white hats in play is not known (rhetorical question, what are the odds the tallest dwarf's hat is black if he turns to find that all nine hats in front of him are white? I don't know, but odds are high that the giant is a sadistic bloke). The original post I viewed is here. http://www.businessinsider.com/toughest-job-interview-questions-2013-7#a-dwarf-killing-giant-lines-up-10-dwarfs-from-shortest-to-tallest-each-dwarf-can-see-all-the-shortest-dwarfs-in-front-of-him-but-cannot-see-the-dwarfs-behind-himself-the-giant-randomly-puts-a-white-or-black-hat-on-each-dwarf-no-dwarf-can-see-their-own-hat-the-giant-tells-all-the-dwarfs-that-he-will-ask-each-dwarf-starting-with-the-tallest-for-the-color-of-his-hat-if-the-dwarf-answers-incorrectly-the-giant-will-kill-the-dwarf-each-dwarf-can-hear-the-previous-answers-but-cannot-hear-when-a-dwarf-is-killed-the-dwarves-are-given-an-opportunity-to-collude-before-the-hats-are-distributed-what-strategy-should-be-used-to-kill-the-fewest-dwarfs-and-what-is-the-minimum-number-of-dwarfs-that-can-be-saved-with-this-strategy-11 Moins

What is the minimum number of dwarfs that can be saved with this strategy? 9 First of all, let's numerate the dwarfs as N1, N2, N3, etc. with N10 being the tallest. Now, N10 will state the color of N9 as his own answer, "My hat is WHITE". Based on this answer, N9 will state his color with a positive statement if the color of N8 is the same as his, "My hat is WHITE". Based on N8's answer, N8 knows that his color is WHITE, now, he will state his color depending on N7. Let's say N7 is black, so N8 will state, "My hat is NOT BLACK". N7 knows that his color is BLACK, but N6 is white, so he will use a negative statement, "My hat is NOT WHITE" and so on. Full example: N10 = BLACK N9 = WHITE N8 = WHITE N7 = BLACK N6 = WHITE N5 = WHITE N4 = WHITE N3 = BLACK N2 = BLACK N1 = WHITE N10: My hat is WHITE (Dies) N9 = My hat is WHITE N8 = My hat is NOT BLACK N7 = My hat is NOT WHITE N6 = My hat is WHITE N5 = My hat is WHITE N4 = My hat is NOT BLACK N3 = My hat is BLACK N2 = My hat is NOT WHITE N1 = My hat is WHITE N10 will have a 50/50 chances of survival... I'm sorry N10, I couldn't save you :'( Moins

the question does not mention that there will be equal number of white and black hats ! Moins

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Burnbrae Farms
On a demandé à QA...10 octobre 2019

what's your daily duty of current company?

17 réponses

Quality Line inspection and first sample & final inspection

Currently I am not working because covit 19 Pandamic

Line inspection and final inspection

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Amazon

Find the union of two strings?

14 réponses

public static void UnionOfStrings() { String s1 = "XYZ"; String s2 = "YZOP"; String s3 = s1.concat(s2); char ch[] = s3.toCharArray(); Set setChars = new TreeSet(); for(char c : ch) { setChars.add(c); } System.out.println(setChars.toString()); } Output : [O, P, X, Y, Z] Moins

public static void IntersectionOfStrings() { String s1 = "XYZYYP"; String s2 = "YZOPP"; Set setChars = new TreeSet(); char c[] = s1.toCharArray(); for(char x : c) { if(s2.indexOf(x)!=-1) { setChars.add(x); } } System.out.println(setChars.toString()); } OUTPUT : [P, Y, Z] Moins

public static void IntersectionOfStrings() { String s1 = "yybbb78"; String s2 = "y7"; if(s1.length() > s2.length()) intersect(s1,s2); else intersect(s2,s1); } public static void intersect(String first, String second) { Set setChars = new TreeSet(); char c[] = first.toCharArray(); for(char x : c) { if(second.indexOf(x)!=-1) { setChars.add(x); } } System.out.println(setChars.toString()); } Moins

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Clearleap

Draw a bridge and you have three people trying to cross? Seriously>

12 réponses

I actually had an interview with Clearleap yesterday and I can tell you that above comments are not true. Interview process was very professional. Problem solving questions were quite interesting and I enjoyed them! Moins

Unfortunately, your response is quite immature and therefore I withdraw myself from this conversation. Moins

4 people actually (you missed the requirement). Looks like you did not pay attention during the interview. These types of questions are designed to figure out your: a) Problem solving skills b) Creativity c) Ability to work under pressure And most of all to observe your thought process. But in your Senior QA Engineer role you should have know about that already, right? Moins

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S&P Global

I was confused between Load and Stress Testing....and one particular Test Case I interpreted wrongly

11 réponses

hey buddy can you please contact me at vishuvashishth3@gmail.com

hey..can someone plz help me out with some expected questions/word puzzles in d 4rth round? i have my interview tomorrow.. My id is aliyashaista@gmail.com Moins

given to anwers

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