The above answers is for 8 balls.
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Question d'entretien d'embauche
Entretien de Applications Support Analyst/Consultant Toronto, ON
FDM GroupYou have 20 balls all equal in size. They all weigh the
same except for one. How do you identify the one that weighs less or more?
Réponse de l'entretien
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The above answer doesn't work. The unique ball can weigh less or more than the other balls. You assumed the unique ball is the heavier one.
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If we can do as many times as we want, just random pick 2 balls. If they have equal weight, compare with the rest. If not, just pick the third one to find out which One is the exception.
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• Break the balls into the following groups: (1, 2, 3), (4, 5, 6), (7, 8)
• Step 1. Weigh (1, 2, 3) against (4, 5, 6)
Two possible outcomes:
The two groups are equally heavy. (Case A)
One of these groups is heavier than the other. (Case B)
• Case A >> Weigh 7 against 8. Now you have identified the heavier ball in 2 weighing.
• Case B >> Take the heavier group (assume it to be (1, 2, 3)), take any two balls and weigh them against each other. Either one of these is heavier else the third ball is.